I made an Voice/Video phone call in an easy Asterisk environment User1000--------Asterisk Server---------User2000 Then I captured the traffic using wireshark. Code: Voice G.711 Video H.263 So, How to calculate the 'average sending bit rate' for voice / video ? Someone told me that the Wireshark-->Statistics-->protocol hierarchy could do this. So, I went to see the details of it. But there are only 'Mbit/s' and 'End Mbit/s'. I found that the Packet number of 'RTP' is 30392 and the packet number of 'ITU-T Recommendation H.263' is 8979. Then, the 'end packets' of 'RTP' is 21413 (maybe is 30392-8979). So, I guess maybe I should use 'End Mbit/s' of RTP as the 'average sending bit rate' of voice packets and the 'End Mbit/s' of 'ITU-T Recommendation H.263' as the 'average sending bit rate' of video packets. Does these correct ? Thanks for your help ! CARL asked 06 Dec '12, 04:20  CARL YU |
One Answer:
Well the payload size for the voice is worked out as 64kbps for the sampling rate with 10ms sampling intervals = (64*10)/8 = 80 bytes the default voice payload size is 20ms which = 160 Bytes for G.711 for the H.263 i am struggling to find info on for my assignment aswell ;) source for the voice: http://www.cisco.com/en/US/tech/tk652/tk698/technologies_tech_note09186a0080094ae2.shtml & lecture slides answered 07 Dec '12, 16:15  vade edited 07 Dec '12, 16:17 |
