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I made an Voice/Video phone call in an easy Asterisk environment User1000--------Asterisk Server---------User2000

Then I captured the traffic using wireshark.

Code: Voice G.711 Video H.263

So, How to calculate the 'average sending bit rate' for voice / video ? Someone told me that the Wireshark-->Statistics-->protocol hierarchy could do this. So, I went to see the details of it. But there are only 'Mbit/s' and 'End Mbit/s'.

I found that the Packet number of 'RTP' is 30392 and the packet number of 'ITU-T Recommendation H.263' is 8979. Then, the 'end packets' of 'RTP' is 21413 (maybe is 30392-8979). So, I guess maybe I should use 'End Mbit/s' of RTP as the 'average sending bit rate' of voice packets and the 'End Mbit/s' of 'ITU-T Recommendation H.263' as the 'average sending bit rate' of video packets. Does these correct ?

Thanks for your help !

CARL

asked 06 Dec '12, 04:20

CARL%20YU's gravatar image

CARL YU
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accept rate: 0%


Well the payload size for the voice is worked out as 64kbps for the sampling rate with 10ms sampling intervals = (64*10)/8 = 80 bytes the default voice payload size is 20ms which = 160 Bytes for G.711

for the H.263 i am struggling to find info on for my assignment aswell ;)

source for the voice: http://www.cisco.com/en/US/tech/tk652/tk698/technologies_tech_note09186a0080094ae2.shtml & lecture slides

permanent link

answered 07 Dec '12, 16:15

vade's gravatar image

vade
11
accept rate: 0%

edited 07 Dec '12, 16:17

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question asked: 06 Dec '12, 04:20

question was seen: 4,810 times

last updated: 07 Dec '12, 16:17

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