Frame 1 (42 bytes on wire, 42 bytes captured)
Ethernet II, Src: AsustekC_b3:af:31 (00:18:f3:b3:af:31), Dst: Broadcast (ff:ff:ff:ff:ff:ff)
Destination: Broadcast (ff:ff:ff:ff:ff:ff)
Address: Broadcast (ff:ff:ff:ff:ff:ff)
.... ...1 .... .... .... .... = IG bit: Group address (multicast/broadcast)
.... ...0 .... .... .... .... = LG bit: Locally administered address (this is NOT the factory default)
Source: AsustekC_b3:af:31 (00:18:f3:b3:af:31)
Address: AsustekC_b3:af:31 (00:18:f3:b3:af:31)
.... ...0 .... .... .... .... = IG bit: Individual address (unicast)
.... ..0. .... .... .... .... = LG bit: Globally unique address (factory default)
Type: ARP
Address Resolution Protocol (request)
Hardware type: Ethernet (0x0001)
Protocol type: IP (0x0800)
Hardware size: 6
Protocol size: 4
Opcode: request (0x0001)
Sender MAC address: AsustekC_b3:af:31 (00:18:f3:b3:af:31)
Sender IP address: 172.26.1.25 (172.26.1.25)
Target MAC address: 00:00:00_00:00 (00:00:00:00:00:00)
Target IP address: 172.26.1.33 (172.26.1.33)
I need to know:
1. highest level protocol that is carried in this frame?
2. type of packet that this protocol message is encapsulated in?
3. the EherType value (in Hex) that identifies this protocol?
I know it's probably all right there in front of me but I'm really new at this and can't seem to decipher it.
asked 29 Jan '11, 15:02
GeekyKitty
1●1●1●1
accept rate: 0%
edited 29 Jan '11, 16:56
SYN-bit ♦♦
17.1k●9●57●245